capacity (equal concentrations of acetic acid and sodium acetate), and another contains
10.0 mL of pure water. Calculate the hydronium ion concentration and the pH after the
addition of 0.25 mL of 0.10 M HCl to each one. What accounts for the difference in the
hydronium ion concentrations? Explain this based on equilibrium concepts; in other words,
saying that “one solution is a buffer” is not sufficient.
Ka of acetic acid = 1.8 x 10^-5
Acetic acid/sodium acetate buffer
Acetic acid .1M
Sodium acetate .1M
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