PbI2(s) + 2e Pb(s) + 2I– Eo = – 0,365 V
AgNO2(s) + e Ag(s) + NO2– Eo = + 0,564 V
Pb2+ + 2e Pb(s) Eo = – 0,126 V
Ag+ + e Ag(s) Eo = 0,80 V
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