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500 ml of 0.150M NaOH is added to 595 mL of 0.200M weak acid (Ka = 1.26x10^-5) what is the pH of the resulting buffer?

This question was answered on Jan 23, 2013. View the Answer
500 ml of 0.150M NaOH is added to 595 mL of 0.200M weak acid (Ka = 1.26x10^-5) what is the pH of the resulting buffer?

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This question was asked on Jan 23, 2013 and answered on Jan 23, 2013.

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