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A 1.00 kg gold bar at 1010 K is dropped into 0.750 kg of sand at 25 C. Assuming no heat is lost to the atmosphere, what is the final temperature of

A 1.00 kg gold bar at 1010 K is dropped into 0.750 kg of sand at 25 °C. Assuming no heat is lost to the atmosphere, what is the final temperature of the sand?

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Q lost = Q gain
So, Heat lost by Gold = Heat gained by Sand
Heat lost by Gold = Mass of Gold x Specific Heat of Gold x Change in Temperature
Heat gained by Sand = Mass of Sand x Specific Heat of...

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