Consider the coordination of Cu2+ by the tridentate iminodiacetate ligand . When the monoprotonated form, , abbreviated HA , is added to an aqueous solution of Cu2+, the following equilibrium is rapidly established:
Cu 2+ + HA- ----------> CuA + H+
If a solution prepared by combining 100 mL of 0.2 M Cu2+ and 100 mL of 0.2 M HA- is adjusted to pH 1.60 with NaOH, what are the concentrations of Cu2+, HA- , and CuA in the solution? (The Ka for HA- is 4.70 x 10^-10, and K1 for Cu 2+ + A -2 --------> CuA is 4.26 x 10^10.
Hi, Please find the... View the full answer