yawndeezy posted a question Jul 10, 2013 at 4:55pm
In the activity, click on the Keq and ΔG∘ quantities to observe how they are related. Calculate ΔG∘ using this relationship and the equilibrium constant (Keq) obtained in Part A at T=298K: Keq=1.92×1026. Express the Gibbs free energy (ΔG∘) in joules to three significant figures.
answered the question Jul 11, 2013 at 7:54am
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dear student , i am attaching the solution to your question . please find it  

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Go = - RT ln Keq
Or

Go= - 2.303 RT log Keq = - 2.303 RT log (1.921026).

= - 2.303 RT 26.28330 = - 2.303 x 8.3144621 JK 1mol1
x 298 K x 26.28330 = - 149976.8654 J mol1
= - 1.499768654 x 105 J...