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This question was answered on Jul 11, 2013. View the Answer
In the activity, click on the Keq and ΔG∘ quantities to observe how they are related. Calculate ΔG∘ using this relationship and the equilibrium constant (Keq) obtained in Part A at T=298K:
Keq=1.92×1026. Express the Gibbs free energy (ΔG∘) in joules to three significant figures.
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Go gibbs free energy.docx

ΔGo = - RT ln Keq
Or ΔGo= - 2.303 RT log Keq = - 2.303 RT log (1.92×1026). = - 2.303 RT 26.28330 = - 2.303 x 8.3144621 J K −1 mol−1
x 298 K x 26.28330 = - 149976.8654 J mol−1
= -...

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