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Need help calculating the heat released into solution for the 3 reations The Enthalpy Change of a Chemical Reaction Experiment 1 The Enthalpy Change

Need help calculating the heat released into solution for the 3 reations 

The Enthalpy Change of a Chemical Reaction
Experiment 1

The Enthalpy Change of a Chemical Reaction1.  Record the following for each of the three trials:

·  Trial 1

a

Mass of the empty calorimeter (g)

18.6g

b

Initial temperature of the calorimeter (°C)

21.5°C

c

Maximum temperature in the calorimeter from the reaction (°C)

35.0°C

d

Calculate ΔT by subtracting (b) from (c) (°C) ΔT = Tmaximum - Tinitial

35.0°C-21.5°C=13.5°C

e

Mass of the calorimeter and its contents after the reaction (g)

68.74g

f

Calculate the mass of the contents of the calorimeter (g) by subtracting (a) from (e)

68.74g-18.6g=50.14g

g

Calculate the moles of Mg reacted (MW = 24.305 g/mole)

?

50mL of 1M HCI is 50/1000x1=0.05

.15/24.305=.006g/mole

·  Trial 2

a

Mass of the empty calorimeter (g)

18.6g

b

Initial temperature of the calorimeter (°C)

21.5°C

c

Maximum temperature in the calorimeter from the reaction (°C)

44.0°C

d

Calculate ΔT by subtracting (b) from (c) (°C) ΔT = Tmaximum - Tinitial

44.0°C-21.5°C=22.5°C

e

Mass of the calorimeter and its contents after the reaction (g)

68.83g

f

Calculate the mass of the contents of the calorimeter (g) by subtracting (a) from (e)

68.83-18.6=50.23

g

Calculate the moles of Mg reacted (MW = 24.305 g/mole)

.25/24.305=.010g/mole

·  Trial 3

a

Mass of the empty calorimeter (g)

18.6g

b

Initial temperature of the calorimeter (°C)

21.5°C

c

Maximum temperature in the calorimeter from the reaction (°C)

52.9°C

d

Calculate ΔT by subtracting (b) from (c) (°C) ΔT = Tmaximum - Tinitial

52.9°C-21.5°C=31.4°C

e

Mass of the calorimeter and its contents after the reaction (g)

68.92g

f

Calculate the mass of the contents of the calorimeter (g) by subtracting (a) from (e)

68.92g-18.6g=50.32

g

Calculate the moles of Mg reacted (MW = 24.305 g/mole)

.35/24.305=.014g/mole

2.  Calculate the heat released into the solution for the 3 reactions, according to the formula:

qreaction= (Ccal * ΔT) + (mcontents* Cpcontents* ΔT)


Top Answer

1) Since the Ccal is not mentioned I will assume it to be zero Qreaction = m x Cp x dT ; Cp for water based systems is 4.18... View the full answer

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