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# In the activity, click on the K eq and G quantities to observe how they are related. Calculate G using this relationship and the equilibrium constant...

In the activity, click on the Keq and ΔG∘quantities to observe how they are related. Calculate ΔG∘ using this relationship and the equilibrium constant (Keq) obtained in Part A at T=298K:

Keq=1.92×1026

Express the Gibbs free energy (ΔG∘) in joules to three significant figures.

The following values may be useful when solving this tutorial.

 Constant Value E∘Cu 0.337 V E∘Fe -0.440 V R 8.314 J⋅mol−1⋅K−1 F 96,485 C/mol T 298 K

kindly view the attached file... View the full answer

• Josse
• Jul 20, 2016 at 12:40am
• But , G = - RT lnkeq Delt G = - 8.314 x 298 x ln 1.92^26 . Thus delt.G = -149941 J delta G = -149.9kJ
• Josse
• Jul 20, 2016 at 12:44am

Delta G = - RT lnkeq delta G = - 8.314 x... View the full answer

Gibbs free energy (Δ G ∘)  =... View the full answer

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