View the step-by-step solution to:

# Concentrations # of drops # of drops # of drops Stock Solution Stock Solution Reaction (after mix-ing in well) Reaction (after mix-ing in well)

 Concentrations # of drops # of drops # of drops Stock Solution Stock Solution Reaction (after mix-ing in well) Reaction (after mix-ing in well) Reaction Time (seconds) Reaction Rate (sec-1) Well # HCl H2O Na2S3O3 HCl Na2S3O3 HCl Na2S3O3 Trial 1 Trial 2 Avg. C1,D1 12 0 8 1M 0.3M 28.46 28.62 28.54 0.035 C2,D2 6 6 8 1M 0.3M 37.63 37.66 37.65 0.027 C3,D3 4 8 8 1M 0.3M 46.31 46.69 46.50 0.022

 Concentrations # of drops # of drops # of drops Stock Solution Stock Solution Reaction (after mix-ing in well) Reaction (after mix-ing in well) Reaction Time (seconds) Reaction Rate (sec-1) Well # HCl H2O Na2S3O3 HCl Na2S3O3 HCl Na2S3O3 Trial 1 Trial 2 Avg. C4,D4 8 0 12 1M 0.3M 24.78 25.00 24.89 0.040 C5,D5 8 6 6 1M 0.3M 50.66 52.41 51.54 0.019 C6,D6 8 8 4 1M 0.3M 100.29 96.16 98.23 0.010

Determine the rate law for the reaction you observed. You will need to either calculate, as described in the lab write up, or by inspection as described in the module. The reaction rate order for each reactant needs to be figured out as well as the value for the constant, k.

Using the rate law that you determined for the reaction above, predict the rate of the reaction if the concentration of HCl was changed to 0.12M and the concentration of Na2S2O3 is 0.12M.  This is a calculation that should result in one answer; rate = ####. SHOW YOUR WORK.

Rate1/rate2 = k [HCl] a [Na2S2O3] b /k [HCl] a [Na2S2O3] b 28.62/37.66 = k [12] a [8] b /k [6] a [8] b 0.7599 = [12] a... View the full answer

• Check the right answer
• rghosh1976
• Jul 20, 2016 at 11:29am
• pl choose and rate
• rghosh1976
• Jul 20, 2016 at 11:29am
• so which answer is for the constant K, and which one is for the 0.12M HCl and Na2S2O3. Because there are two different questions there. Thanks
• Jul 20, 2016 at 7:06pm
• After getting the K I have calculate for 0.12M , k is k = 2.808 M-1s-1
• rghosh1976
• Jul 20, 2016 at 9:29pm
• rate = 54.067 sec-1 for 0.12M HCl and Na2S2O3
• rghosh1976
• Jul 20, 2016 at 9:29pm

Here is the answer... View the full answer

1 comment
• ka_moderator
• Jul 21, 2016 at 1:34pm

### Why Join Course Hero?

Course Hero has all the homework and study help you need to succeed! We’ve got course-specific notes, study guides, and practice tests along with expert tutors.

### -

Educational Resources
• ### -

Study Documents

Find the best study resources around, tagged to your specific courses. Share your own to gain free Course Hero access.

Browse Documents