The uniform panel door weighs 56 lb and is prevented from opening by the strut C, which is a light two-force member whose upper end is secured under the
door knob and whose lower end is attached to a rubber cup which does not slip on the floor. Of the door hinges A and B, only B can support force in the
vertical z—direction. Calculate the compression C in the strut and the horizontal components of the forces supported by hinges A and B when a horizontal
force P = 48 lb is applied normal to the plane of the door as shown. Answers:
C = 110.557 lb
Axy= 57.2766 lb Bxy= fl 64.0632 lb