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The 50-lb block rests on the rough surface for which the coefficient of kinetic friction is 0. A force F = (40 + s2) lb, where s is in ft, acts on...

The 50-lb block rests on the rough surface for which the coefficient of kinetic friction is 0.2. A force
F = (40 + s2) lb, where s is in ft, acts on the block in the direction shown. If the spring is originally unstretched
(s = 0) and the block is at rest, determine the power developed by the force the instant the block has moved
s = 1.5 ft.

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