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Is there a better way to solve this problem?

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Question 4: The number e is an important mathematical constant that is the base of the natural logarithm. e also arises in the study of compound interest, and in many other applications. Background of e: ht s: en.wiki edia.or wiki E mathematical constant) e can be calculated as the sum of the inﬁnite series: _ 1 1 1 1 9'1+E+Z+§+Z+ The value of e is approximately equal to 2.71828. We can get an approximate value of e, by calculating only a partial sum of the inﬁnite sum above [the more addends we add, the better approximation we get). Implement the function def e_approx (n) . This function is given a positive integer n, and returns an approximation of e, calculated by the sum of the ﬁrst [n+1] addends of the inﬁnite sum above. To test your function, use the following main: def main(): for n in range(15): curr_approx = e_approx(n) approx_str = &quot;{:.15f}&quot;.format(curr_approx) print (&quot;n =&quot; , n, &quot;Approximation: &quot; , approx_str) N gte: Pay attention to the running time of e_approx. By calculating the factorials over for each addend, your running time could get inefficient. An efficient implementation would run in @(n).