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The problem is "Using divide and conquer algorithm, find a maximum subsequence sum." My question is

from the codes below that how it works. "int maxLeftSum=MaxSub(Alist,Start,Center); " I'm guessing, Center =3 , after MaxSub is called Center=1, after MaxSub is called Center =0, then return with 4 ? ============================================================ public class SubSequence{ public static void main(String[] args){ int Alist[]={4,-3,5,-2,-1,2,6,-2}; int Start=0; int End=Alist.length-1; int num=MaxSub(Alist,Start ,End ); System.out.println("maxSum is: "+num); } public static int MaxSub(int Alist[],int Start,int End){ int leftBordersum=0, rightBordersum=0; int maxLeftBorderSum=0, maxRightBorderSum=0; int maxMiddleSum; if(Start==End) if(Alist[Start]>0) return Alist[Start]; else return 0; int Center=((Start+End)/2); int maxLeftSum=MaxSub(Alist,Start,Center); int maxRightSum=MaxSub(Alist,Center+1,End); for(int i=Center; i>=Start; i--){ //Counting down leftBordersum+=Alist[i]; if(leftBordersum>maxLeftBorderSum) maxLeftBorderSum=leftBordersum; } for(int i=Center +1; i<=End; i++){ // Counting up rightBordersum+=Alist[i]; if(rightBordersum>maxRightBorderSum) maxRightBorderSum=rightBordersum; } maxMiddleSum=maxLeftBorderSum+maxRightBorderSum; int maxSum=0; if(maxLeftSum>maxRightSum && maxLeftSum >maxMiddleSum){ //return maxLeftsum maxSum=maxLeftSum; }else if(maxRightSum>maxLeftSum && maxRightSum>maxMiddleSum){ maxSum=maxRightSum; }else if(maxMiddleSum>maxLeftSum && maxMiddleSum>maxRightSum){ maxSum=maxMiddleSum; } return maxSum; } }

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Dear Student Please find... View the full answer

Computer Science - 8361687.doc

publicclass Subsequence{
publicstaticvoid main (String args){
intAlist={4,-3,5,-2,-1,2,6,-2};
int Start=0;
int End=Alist.length-1;
intnum=MaxSub(Alist,Start ,End );
System.out.println(&quot;maxSum...

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