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DWd / ^ ^&h , W KE >/E D W WZ KWz d D WD KE >/E D > d d z / z d d D & z D1 D J0 0 2x1 MUX 1 Y S J K0 K Q Q1 Q Q0 DWd / ^ ^&h , W...

please do question 2 on the attached file
CMPT 150, Spring 2013, SFU Harbour Centre Page 1 of 2 Instructor: Diana Cukierman Assignment#4. Due date: ON LINE - Monday March 25, 9:00 PM ON LINE PAPER COPY - Tuesday March 26 at the beginning of the Labs. This assignment may be done in teams of two people each. This assignment does not include design works implementation, but just paper and pen/cil work. You may implement the circuits in design works to observe the behavior but this is not required. A solution will be posted immediately after the deadline; hence no postponement of the deadline will be possible. If you do not submit at least the on line version before the solutions are posted your assignment cannot be marked. You certainly may submit earlier. The topics included in this assignment are part of what is being tested in the midterm, on Tuesday March 26. 1 . 2’s complement exercises: Exercise 4-7, current edition (Exercise 5-7 previous edition) 2 . Analyze the sequential circuits in Figures 1 and 2, providing the associated entity definitions diagrams, the state tables, the state diagrams and any intermediate work done. You may want to simplify the Boolean equations you obtain to more easily build the state table. S MUX K0 J0 Q0 D1 Q1 1 0 Y 2x1 J K Q D Q
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CMPT 150, Spring 2013, SFU Harbour Centre Page 2 of 2 Instructor: Diana Cukierman Figure 1. Figure 2. End of Assignment #4 DC DA C DB A B Z 1 0 1 2x1 MUX 4x1 MUX 2 Y 0 0 1 3 S Q D Q D D Q
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Hi dcheon. Please... View the full answer

Question 8442220.docx

First, we need to simplified the circuit only using D-Flip flop, and we may decompose
the 2x1 MUX to be a logic circuit in gate level. From the circuit above, we get the boolean formula : Truth...

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