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# Below are eight mctions. Find the rst derivative of each. Space is provided. All of the derivatives can be found by using combinations of the...

Below are eight ﬁmctions. Find the ﬁrst derivative of each. Space is provided. All of the
derivatives can be found by using combinations of the constant rule, power function rule and
sum-difference rule. Do not use the product rule. It is not needed. The degree of diﬁculty
(more or less) increases ﬁ‘om (a) to (h). Be sure to show intermediate work. Check the scoring
rubric to see how the points will be awarded. For example, the ﬁrst derivative of the function: Y: (2): + 3)2 is g = 2(2X+ 3)(2)
Although this can be simpliﬁed to: g = 8X +1.2
Hint: To make either (g) or (h) easier, multiply the two parts together ﬁrst, then ﬁnd the
derivative of the resulting product. This avoids the need to use the product rule. Good
Luck! a) Y=GQ3—SQZ+GQ—5 51) T=U5”+2U5”—3U&quot;”
m= new b) Y=10+4X4—3X2 g) I1V=3V‘—45+2V3
W= wig: c) Q=P3’3—P‘3’3+P i) U=5V3+3V‘3—5V3+15
W: wfﬂ= g) z =3W2[2+3W2)
W: h) z = 4X1”(2X— 3X“)
m=

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