Example (cont.) KVL: Loop 1: - 10 + , + v3 = 0 Loop 2: - V3 + V2 + 12= 0 Loop 3 (outer loop): -10 + +V2 + 12=0 Note that Equation (3) is linearly...
View the step-by-step solution to:

Question

Employ Mathcad to solve symbolically the set of Equations 1,2, and 4.


src="/qa/attachment/10454404/" alt="005.png" />

005.png

Example (cont.)
KVL:
Loop 1: - 10 + , + v3 = 0
Loop 2: - V3 + V2 + 12= 0
Loop 3 (outer loop): -10 + +V2 + 12=0
Note that Equation (3) is linearly dependent on (can be derived
from) Eqn. (1) and (2), so we ignore it. We have three unknowns
and two equations. So, we need a third equation in the voltage
variables. This can be obtained by applying KCL at node a:
i1 - 12 - 13 = 0 -
V1
V2
V3
R1
R2
R3
= 0
(4)
Given numerical values for the resistors, Equations (1), (2) and
(4) can be solved for the voltages v1, V2 and v3.

Recently Asked Questions

Why Join Course Hero?

Course Hero has all the homework and study help you need to succeed! We’ve got course-specific notes, study guides, and practice tests along with expert tutors.

  • -

    Study Documents

    Find the best study resources around, tagged to your specific courses. Share your own to gain free Course Hero access.

    Browse Documents
  • -

    Question & Answers

    Get one-on-one homework help from our expert tutors—available online 24/7. Ask your own questions or browse existing Q&A threads. Satisfaction guaranteed!

    Ask a Question
Ask Expert Tutors You can ask 0 bonus questions You can ask 0 questions (0 expire soon) You can ask 0 questions (will expire )
Answers in as fast as 15 minutes