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A controlled half-wave rectifier has an ac source of 240 Vrms at 60 Hz. The load is 30 ohm resistor. Determine: a)

the delay angle such that the average load current is 3 A. b) the power absorbed by the load c) the power factor 

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Ele 2.jpeg

output voltage
Vo, rms = Vaz /
1 - 4 + sin 2xx
By substituting the values
Vo, ri = 240 12
1 - 0-84 + + Sin 2/0. 842)
= 160 . 08 V
I output current in
= Vo,rms
= Voi rms
160 .08 v

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