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i don't understand why the current across the

impedence 0.2+j0.6 is also I of N as well. Also, I don't understand why Zeq only counts to 0.2+j0.6 not contains 10-j19


Thank you so much!

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EE 233 A Wi 20 X
Slide 1
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PowerPoint Pre X PowerPoint Pre X
YASH X A How to Use Th X C Get Homework X
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->
C O C:/Users/USER/Downloads/EE%20233%20Lecture%208.pdf
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Building Java Prog... 0 [93] #202...
MERCER - RCE.
SOURCE TRANSFORMATION AND
THEVENIN-NORTON EQUIVALENT CIRCUITS
IN and Zs appear the easiest to be solved,
To find IN by shorting a-b
IT
IN
1 + j3
0.2 + j0.6
404(0)
9 - j3
10 - j19
V's
IT = Zea
, where Vs = 404(09)
Zeq = (1 + j3) + [(9 - j3) ll (0.2 + jo.6)]
1.239 + j3.584 = 3.792(70.929)
TOT
X
F + 06:49
2020/2/11

Top Answer

This is because 10 -j19 is in parallel with short... View the full answer

explanation.jpeg

An lets consider given cirrust
1+13
OR+job
10 -319
LIN
Parallel.
this is because 10-319 is in parallel with shortarrai.
So when any impedane is cross a short lived
it has No effect and can be...

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