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the voltage across a 43mH inductor is given by v(t)=50cos(wt+6)V.

the voltage across a 43mH inductor is given by v(t)=50cos(wt+6)V. find the peak current at a frequency f=(a) 1/50Hz, (b) 1Hz, (c) 30Hz, and (d) 1MHz
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528739_ELEC.doc

Peak Current= E/(w*L)
E is Max. Voltage
w=angular frequency=2*Π*f, Π=3.14
E=50 V
L= 43*10^(-3) H
a)f=1/50 hz
i= 50/(2*3.14/50*43*10^(-3))
= 9253.19 A
b)f=1 hz
=>i = 50/(2*3.14*1*43*10^(-3))...

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