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Question #13: Which of your simulated cross or crosses do the data from the Punnett
Square most closely fit? Why?
Question #14: A wild-type fly (heterozygous for gray body color and normal wings - b*
vg /b vg) was mated to a black fly with vestigial wings (b vg/b vg). The F1 had the
following phenotypic distribution: wild type, 850; black body - vestigial wings, 899;
black body - normal wings, 79; gray body - vestigial wings, 85. What is the
recombination frequency (RF) between these genes for body color and wing type? (show
work)
Question #15: A cross produced 915 offspring with normal pigment and 310 with albinism.
Conclusion?
a. One of the parents was homozygous for albinism.
b. Both parents were heterozygous.
C. One parent was homozygous for normal pigmentation.
d. Both parents were albinos.
e. 605 albino zygotes must have failed to develop.

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13) I am not 100% certain of what the "simulated cross(es)" are exactly, however, if this refers to the various phenotypic... View the full answer

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