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why is it 4,113 for D5 ~ D8? is that because SL

method for year 5 is same is DDB method year 5one? so that the rest have to be 4,113?

can you please help me out understand?

Question 2.png

4) Compute the depreciation each year of a machine that costs $50,000 to purchase. and $2,000
to install with an 8-year life. Use the DDB method (multiplier = 2) switching to straight line _
depreciation when appropriate. Assume a salvage value of $0.
1/ 2) 7. 25
D1 = 13,000
n
Bn
DDBA
5 Ln
D2 = 9,750
0 52k
Note:
D3 = 7,3/2
1 39 k
( 13,000
DDBn =
8
52K = 6, 500
D1 = 5485
2 29250
9,750
39k/2 = 5,57/
Ds - 4,113
3 21938
7312
2925 = 4, 175
:, 25 ( BD- )
Do = 4,/13
4 1 6, 453
(5, 485
21,935 = 4387
5
4,113
16,483
D7-4,113
4, 113/
D: = 4173

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