Consider the following LP model: Max4X1+ 6X2 6X1+ 4X2 24 X2 3 5X1+ 10X240 X1, X2 0 The solution to this model is:
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Question

Consider the following LP model:

Max 4X1 + 6X2

6X1 + 4X2 ≤ 24

X2 ≤ 3

5X1 +

10X2 ≤ 40

X1, X2 ≥  0

The solution to this model is:


Unbounded


Infeasible


Not unique


Degenerate


Redundant

Top Answer

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New Doc 2019-10-02 00.08.52_1.jpg

Max
* = lou+ 62 2
condition
624 + 4212 - 24
912 - 3
524 + 10 212 2 40
24 , 262 7, 0
Now Taking
6 09 + 401, = 24
or 604 + 406 2 24
8 1504 + 102, 2 40 or 504 + 102 = 40
624 + 4012 = 24
or
04 = 24-...

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