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Please help me in answering the following geometry question.




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B) 2.11: Unit Test - MTH208A_Geom X
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< BACK TO 2.11: UNIT TEST - MTH208A_GEOMCA_SEC31_SEM1_19-20
A conjecture and the paragraph proof used to prove the conjecture are shown.
Given: ABCD is a parallelogram.
DC bisects ZBDE
Prove: 21 = 23
Drag an expression or phrase to each box to complete the proof.
It is given that ABCD is a parallelogram, so AB || DC by the definition of parallelogram.
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2019-10-14 09.24.37.jpg

1: Unit Test - MTH208A_Geom x
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ACK TO 2.11: UNIT TEST - MTH208A_GEOMCA_SEC31_SEM1_19-20
Drag an expression or phrase to each box to complete the proof.
It is given that ABCD is a parallelogram, so AB || DC by the definition of parallelogram.
So, 21 ~ 42 by the alternate interior angles theorem. It is also given that DC' bisects
LBDE , so /2 ~
by the
Therefore,
~ Z3 by the
transitive property of congruence
definition of angle bisector
22
23
9
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Top Answer

<2 = <3 by the definition of angle... View the full answer

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