Below are the blue Since one INDICATOR Named below are results of the numbers (namely -1/5) remains Below is the result 4 row operations row
View the step-by-step solution to:

Question

# the picture is a simplex matrix and I

am confused. The starting point is the matrix circled in blue and the answer is the matrix on the bottom right. I would like help with how to get from the matrix in circled in blue to the matrix on the bottom right. if possible break it down step by step so it is easier to understand.

Below are the
blue
Since one INDICATOR
Named below are
results of the numbers
(namely -1/5) remains
Below is the result
4 row operations
row operations are the
negative, we must
of changing our pivot
needed to pivot
named above new ISM
repeat steps 3-9
to &quot;1&quot;
on the number(16/5)
encircled in red
RATIOS
0 0
8
SEE
0
0
0
5
8
1 - 8/2 = R
0 1
#2
1 16
1642 -5 - BELOW
0
5
16
0
18
0 0
5
6
( 8 ) 12 = R2
10 05
6 5
Er2 = Rg
0 3 0 09
0
3 0 0 3
1 12 4+5 2-84
PIVOT COLUMN
(PIVOT ROW )
TO
UINDICATOR, ROW
MATRIX
BELOW
X1 X2
X3
\$1
\$2
0
0
0
Above there was a tie for least non-negative ratio:
either row 1 or row 2 could have become the pivot row, and either
5
0
Col
16
choice leads to the final tableau after one additional pivoting At the
right is the result of the final 3 row operations
Col-
0
0
16
13
INDICATOR ROW
All indicators (0. 0. 0. . and , } are now zero or bigger (&quot;13&quot; is NOT an indicator)
Thus, as in step 8 of the SIMPLEX METHOD, the last tableau is a FINAL TABLEAU
Row operations of SIMPLEX METHOD are done
Thus, the basic solution for the tableau above is the solution to our

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