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Question 1: [25 points] Solve the following questions about probability. Part A: (5 points) Suppose I was looking at computers and was considering 3

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Question 1: [25 points] Solve the following questions about probability. Part A: (5 points) Suppose I was looking at computers and was considering 3 brands, 2 different styles (laptop vs desktop], and 4 colors. How many possible options
are there? 3x2x4 = 24 Part B: (5 points] Using the table below, what is the probability that a randomly selected students earns an ‘A’ in the course? Grade Frequency A 7 B 11 C 14 D 5 F 2
m = 0.219 = 22% Part C: [5 points) In the table above in Part B, the probability of not earning an ’A’ is 1— 0.219 = 0.781 =78% Part D: {5 points) In the table above in Part B, the probability of earning an 'A or B’ is 7+11 18
— = — = [1857:8596
14+5+2 21 Part E: [5 points) Which ofthe following are not valid probabilities? 0, 1.00, 100%, 81?, 4102596 8/? and —0.025% Question 2: [25 points) A random sample of 100 customers at a local jewelry store was selected. They were asked what cut of diamond they prefer: princess,
emerald, or round. The data is presented in the following table. If 1 person is selected at random, find the probability ofthe following. lfyou choose to leave your
answers in fraction form, then please reduce as necessary. Diamond cut Preference
Gender Princess Emerald Round Totals
Male 15 12 21 48
Female 20 11 21 52
Totals 35 23 42 100 Part A: [5 points) Find P{Male) 1
—=0.021
48 Part B: [5 points) Find P{Female and Round) 21
— : 0.44 : 44%
4B

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Part C: (5 points] Find P(Male Emeraldl 12
— = 0.25 =25%
43 Part D: {5 points} Find P(Emerald Male 2 3
—:o.43=43%
48 Part E: (5 points} Find PlFemale or Princess) 52 35 20 67
—+—-—= —= U.57=57%
100 100 100 100 Question 3: [25 points] Answer the following questions pertaining to combinatorics. Part A: (5 points) How many distinguishable arrangements are there for the word PHILIPPINES? 11! —: 1108800
3!3!1!1!111!1!
Part B: [5 points) How many ways can I pick 4 of my 6 students to go to Buffalo Wild Wings with me? 5! a!
MOS—4)! — 4!2!_ 15 Part C: (5 points] How many ways can I pick 4 of my 6 students to sit at a table (that holds 4 people} at Buffalo Wild Wings? 6! (6—4)! = 360 Part D: (5 points} Find 6!
720 Part E: (5 points} Suppose I am a District Manager for Walgreens. I have 8 stores in my district: 2 in Bellbrook, 4 in Dayton, 1 in
Centeryille, and 1 in Beavercreek. Suppose I decide to select 4 stores {no store can be selected more than once} at random to visit.
What is the probability that 3 are in Dayton and 1 is in Bellbrook? c 4,3 .6 2,1 4. 2
43,4) 70

Top Answer

Question 1: A) 24, B) 0.1795, C) 0.8205, D) 0.4615, E) 8/7 and... View the full answer

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