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( 1 point ) Perform the Gram- Schmidt process on the following sequence of vectors . * = 4 1 . > = I \ , Z.

Linear system: orthogonal

Why is my last column vector answer is wrong?27575F32-DD81-4AF2-A670-9EA457743D94.jpeg

27575F32-DD81-4AF2-A670-9EA457743D94.jpeg

( 1 point ) Perform the Gram- Schmidt process on
the following sequence of vectors .
* =
4
1 . > =
I
\ , Z. =
- 8
4 / 6
4 / 6
216
2/3
5 /( sqrt 45 )
- 1 13
- 4 / ( sqrt 4 5 )
- 213
- 2 1 ( sart 45 )

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3 comments
  • Thank you for your explanation. I did tried to find the projection on the 2nd vector, where I found 0 on the top. Could you please advise what is the correct formula I should use? Thank you!
    • Aiaiooool
    • Apr 02, 2019 at 4:12pm
  • What you have there, (5,-4,-2) is what remained after you subtracted the projection of the 3rd given vector on the 1st found vector. All that remains is to subtract the projection of the 3rd given on the 2nd found which is 6*(2,-1,-2)/3 = (4,-2,-4). You subtract this: (-5,-4,-2)-(4,-2,-4) = (1,-2,2), and then normalize by division by 3.
    • hwhelp18
    • Apr 02, 2019 at 4:21pm
  • Ok! I got it! Thank you so much!
    • Aiaiooool
    • Apr 02, 2019 at 4:39pm

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