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Find the equation of the line tangent to the graph

of this function at the point where x=1.

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Consider the function g(x)=(3x2-5x)(2x-3)(2x3+5x-6)(4x5-3x2+2x-8). Find the
equation of the line tangent to the graph of this function at the point where
x=-1. Show your work.

Top Answer

The given function is g ( x ) = ( 3 x 2 5 x ) ( 2 x 3 ) ( 2 x 3 + 5 x 6 ) ( 4 x 5 3 x 2 + 2 x 8 ) ... View the full answer

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