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This is a PDEs problem and I need it with 7 hours.

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SOLUTION.docx

SOLUTION: We have ∂u
∂2 u ( )
=D 2 , 1
∂t
∂x
u ( 0,t )=0, ( 2 )
u ( 1,t )=0, ( 3 ) Let u ( x , t )=X ( x ) T (t )= XT be the solution of (1 ) then
∂ XT
∂ 2 XT
=D
2
∂t
∂x X dT
d2 X...

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