April shoots an arrow upward into the air at a speed of 64 feet per second from a platform that is 21 feet high. The height of the arrow is given by the function h(t) = -16t2 + 64t + 21, where t is the time is seconds. What is the maximum height of the arrow?
h(t) = -16t2 + 64t + 21 85... View the full answer
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The max is the vertex of the parabola, h(t) = -16t2 + 64t + 21 where a=-16 b=64... View the full answer