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The solution is... View the full answer

- oh sorry ln (x^2√(y-1)) /(z^5) = ln (x^2√(y-1)) -5ln(z) = ln x^2 +ln√(y-1)) -5ln(z) = 2lnx+(1/2)ln(y-1)-5lnz answer
- yadavrakesh8497
- May 03, 2018 at 1:52pm

- 2lnx+(1/2)ln(y-1)-5lnz answer
- yadavrakesh8497
- May 03, 2018 at 1:53pm

- Let me know if you have any doubt
- yadavrakesh8497
- May 03, 2018 at 1:57pm

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The given log function as the sum and difference of ln with... View the full answer