Eyjafjallajokull is a volcano in Iceland. During a recent eruption, the volcano spewed out copious amounts of ash. One small piece of ash was ejected from the volcano with the initial velocity of 368 ft/sec. The height in H, in feet, of our ash projectile is given by the equation : H = -16t^2 + 368t, where t is time, in seconds.
The graph for this equation will be parabola. We will assume the volcano has no height (i.e. H = 0, t = 0).
1. When does the ash projectile reach the maximum height?
2. What is the Maximum height?
3. When does the ash projectile return to the ground?
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Answer 1: The ash projectile reach the maximum height when t = 11.5... View the full answer