Find the absolute man and min. If either exists, for each function on the indicated intervals.

f(x)=2x^3-3x^2-12x+24

A. (-3,4) B. (-2,3) C. (-2,5)

#### Top Answer

F(x)=2x^3-3x^2-12x+24 First differentiate the provided function: F'(x)=2*3*x^2-3*2*x-12=0 6x^2-6x-12=0 X^2-x-2=0 X^2-2x+x-2=0... View the full answer

#### Sign up to view the full answer

#### Other Answers

max and min exist where the derivative=0 f(x)=2x^3-3x^2-12x+24 f'(x)=6x^2-6x-12 solving the equation above x= 2 and -1... View the full answer

A) The absolute maximum value of the function in the interval (-3,4) is f(4) = 56 And absolute minimum value of the... View the full answer