View the step-by-step solution to:

# The terminal velocity of a person falling through air is about 300Km/hr.The acceleration due to gravity is 10ms^-2.

The terminal velocity of a person falling through air is about 300Km/hr.The acceleration due to gravity is 10ms^-2. What C is in the equation

v'=C[(g/C)-v], where g is the acceleration due to gravity and v is the velocity.

(a) How long does it take for a falling person to reach the 90 percent of this terminal velocity?

t =  _____________

(b) How long to reach 95 percent? t =  __________

(c) How long to reach 99 percent? t =____________

This problem can be solved by... View the full answer

### Why Join Course Hero?

Course Hero has all the homework and study help you need to succeed! We’ve got course-specific notes, study guides, and practice tests along with expert tutors.

### -

Educational Resources
• ### -

Study Documents

Find the best study resources around, tagged to your specific courses. Share your own to gain free Course Hero access.

Browse Documents