**(a)**Suppose that the tangent line to the curve *y* = *f* (*x*) at the point (3, −11) has equation *y* = −5 − 2*x*. If Newton's method is used to locate a root of the equation *f* (*x*) = 0 and the initial approximation is *x*_{1} = 3,find the second approximation *x*_{2}.

**(b)**Suppose that Newton's method is used to locate a root of the equation *f* (*x*) = 0 with initial approximation *x*_{1}= 9. If the second approximation is found to be *x*_{2} = −6, and the tangent line to *f* (*x*) at *x* = 9 passes through the point (18, 5), find *f* (9).

**(c)**Use Newton's method with initial approximation *x*_{1} = 4 to find *x*_{2}, the second approximation to the root of the equation *x*3 = 7*x* + 5.

#### Top Answer

(a) The second approximation x 2 will be: -2.5 (b) The value of f ( 9 ) = 1... View the full answer

- B appears to be wrong :/
- Sugarnutzzz
- May 14, 2018 at 4:16am

- Information is missing, because there is not information about slope of tangent line, so i assumed the previous equation of tangent
- sanyachawla1993
- May 14, 2018 at 4:20am