1)what is the general solution of y ′′(t) = e^2t

2)what is solution of y′ (t) = ky(t) with y(1) = 5 , y′(1) = 4

3)how to solve y ′ (t) = 2(M − y(t)) with y(0) = 3 y′(0) = 2

4)what is the solution solution of y'(t) = 3y(8 − y) with y(0) = 2

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1) The general solution is y = e 2t /4 + C 1 *t + C 2 2) The... View the full answer