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If an object is thrown straight up into the air with an initial velocity of 128 feet per second, then its height above the ground at any time t is...

If an object is thrown straight up into the air with an initial velocity of 128 feet per second, then its height above the ground at any time t is given by the formula h = 128t - 16t2. Find the times at which the object is on the ground by letting h = 0 in the equation and solving for t.

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