(1/cos)^2 times (1/tan)-(1/tan)=tan
(1/cos^2) times (-2/tan)=tan
sq. root of (-2/cos^2)= sq. root of (tan^2)
sq. root of (2i)/cos=tan
I'm not sure if I did this right. If I didn't, can you show me the correct steps?
Thanks, I appreciate it.