View the step-by-step solution to:

sec^2xcotx-cotx=tanx (1/cos)^2 times (1/tan)-(1/tan)=tan (1/cos^2) times (-2/tan)=tan (-2/cos^2tan)times tan=tan(tan) sq. root of (-2/cos^2)= sq....

sec^2xcotx-cotx=tanx
(1/cos)^2 times (1/tan)-(1/tan)=tan
(1/cos^2) times (-2/tan)=tan
(-2/cos^2tan)times tan=tan(tan)
sq. root of (-2/cos^2)= sq. root of (tan^2)
sq. root of (2i)/cos=tan
I'm not sure if I did this right. If I didn't, can you show me the correct steps?
Thanks, I appreciate it.

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