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Let f(x)=(-4e^(x+1))+(e^6).

Let f(x)=(-4e^(x+1))+(e^6).

f'(0)=
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Math-8088198.doc

Let f(x) = -4e(x+1) + e6. Find f’(0)
Solution: The differentiation of f(x) is:
⇒ −4e ( x +1) So f’(0) = -4e(0 + 1) = -4e [Differentiation of e6 would be zero as it is a constant]

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