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Solve the following recurrence relations assuming that n is a power of 2 (leaving a constant A to be determined).

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Solve the following recurrence relations assuming that n is a power of 2 (leaving a constant A to be determined). (1) = + 2n - 1 (2) = 3 + 4 (3) = 16 + 5n (4) = 4 + 3n
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Math-8195563.doc

Solve the following recurrence relations assuming that n is a power of 2 (leaving a constant A
to be determined).
(1)
=
+ 2n - 1
(2)
=3
+4
(3)
= 16
+ 5n
(4)
=4
+ 3n
n = 2k
1) an = an/2 + 2(n) – 1...

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