Assume n = 4k (i.e., k = log4 n) for some k. Solve the following recurrence relation by

iteration.

f (n) =

1 if n = 1

3 f ( n

4 )+n if n 2

iteration.

f (n) =

1 if n = 1

3 f ( n

4 )+n if n 2

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