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Second order differential equation.<br/> I want to convert this second

order diff equ to a set of two first order.
d^2thata/dt^2 +(g/L)sin(theta) = 0, theta(0)=pi/6, theta'(0)=0
g = 32.17 ft./sec^2, L=2ft
Something like this:
u1(t) = theta(t)
u2(t) = theta'(t)
u1'(t) = u2(t)
u2'(t) = -16.085*sin(t) ??? not right

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Solution is...

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Given second order differential equation is :
d2 θ
dt2 g
+ L sinθ = 0 where θ(0) = π , θ (0) = 0
This can be rewritten as: θ (t) + L sinθ = 0 -1) We use change of variables to solve this...

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