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let h(x)=5-4h^3 .

let h(x)=5-4h^3 . compute h'(1)
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H(x) = 5-4x3
We know the derivative of x3 is 3 x2 and derivative of constant is 0..
Hence ,
H’(x) = -4*(3x2)
= - 12x2
H’(1) = -12*(1)2
= -12
b)Now Considering the curve
Clearly (1,1)...

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