Let f:X -> X be a map with fixed points x, i.e. f(x) = x. If 1 is
not an eigenvalue of df_x: T_x(X) -> T_x(X), then x is called a Lefschetz fixed point of f. f is called a Lefschetz map if all its fixed points are Lefschetz. Prove that if X is compact and f is Lefschetz, then f has only finitely many fixed points.
252,291 students got unstuck by Course
Hero in the last week
Our Expert Tutors provide step by step solutions to help you excel in your courses