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# Determine, in polar form in this power complex number (2+j3) 6 .

1. Determine, in polar form in this power complex number (−2+j3)6.

#### Top Answer

(−2+j3)=[(−2)2 +(3)2]∠tan−1 3 −2 = √ 13∠123.69◦, since −2 + j3 lies in... View the full answer

#### Other Answers

find attached... View the full answer

Answer z  =  2197 {... View the full answer

:−
= (−2 + 3 ) ℎ
ℎ = ℎ = −2 + 3 = ℎ (−2) + (3) = = √4 + 9
= √13
= − tan 3
=
|−2|
= =&gt; = =&gt; − tan 3
2 = = = √13

= 2197 6 − 6 tan 3
2 + 6 − 6 tan −6 tan 3...

-2+j3 = sqrt(13) with angle arctan(-3/2) = sqrt(13)... View the full answer

Solution: is given... View the full answer

complex number = (−2+j 3)6.
the magnitude of complex number = sqrt (-22 + 32) = sqrt( 4 +9 ) = sqrt(13)
the tangent angle
tan (theta) = 3/-2
theta = arc tan (-3/2) = - 56.31 degree
then the given...

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