1. Determine, in polar form in this power complex number (−2+j3)^{6}.

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(−2+j3)=[(−2)2 +(3)2]∠tan−1 3 −2 = √ 13∠123.69◦, since −2 + j3 lies in... View the full answer

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find attached... View the full answer

Answer z = 2197 {... View the full answer

-2+j3 = sqrt(13) with angle arctan(-3/2) = sqrt(13)... View the full answer

Solution: is given... View the full answer