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Question exercise 2 i

don't know how to this problem

plz.

give me solutions liberated by the
reaction
absorbed by the
product
If the reaction takes place at T1, the amount of heat liberated is AH3. This heat is.
enough to raise the temperature of the product MO from T, to Ts (AH4).
Therefore the reactants need to be preheated to T1.
3) Fusion is an isothermal phase transformation and hence the enthalpy change of M
fusion of M.
increases without accompanying a temperature change. AH, represents the heat of
Che
Exercises
LIL .
1. The enthalpy change associated with freeze of water at 273K is -6.0kJ/mol. The
heat capacity (Cp) for water is 75.3 J/molK and for ice 37.6 /molK. Calculate the
enthalpy change when water freeze at 263K.
2. The enthalpy changes at 298K and 1 atm for the hydrogenation and for the
combustion of propane are given below:
CHo(g) + H2(g) = C3H8(g)
AH, = -124 kJ/mol
C3H8(g) + 502(8) = 3CO2(g) + 4H20(1)
. AH2 = -2,220 kJ/mol
In addition the enthalpy change at 298K and 1 atm of the following reaction is
known:
H2(g) + 1/202(g) = H2O(1)
AH, = -286 kJ/mol
Calculate the heat liberated by the combustion of one mole of propane at 298K
and 1 atm.

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