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Air at 250 kPA and 15C is being forced into a tire, which has a volume of 0.5m^3, at a velocity of 60 m/s through a 6 mm opening. Find the rate of...

Air at 250 kPA and 15C is being forced into a tire, which has a volume of 0.5m^3, at a velocity of 60 m/s through a 6 mm opening. Find the rate of change of the density in the tire.

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Hi, Please find the... View the full answer

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Solution:
Given Data:
P = 250 KPa
T = 150 C
Volume of tire v = 0.5 m3
Velocity V = 60 m/s
Diameter of the opening D = 6 mm
Now as we know
Mass = Density*Volume
So, m = ρ*v
Differentiating both the...

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