Consider a router that interconnects a packet switched network with 5-bit addresses. Suppose there are three
subnets: Subnet 1, Subnet 2 and Subnet 3. Also suppose that Subnet 1 is required to support at least 6 interfaces, Subnet 2 is to support at least 10 interfaces, and Subnet 3 is to support at least 5 interfaces. Provide three network address prefixes (in binary) that satisfy these constraints.
Subnet 1 needs 6 interfaces so bits required for this interface are: 3 bits (2 3 = 8). Similarly, for subnet 2, 10... View the full answer