The correct answer is 1) KMnO4, H2O, NaOH, heat, 2) H3O+, 3) xs EtOH, H3O+, -H2O, 4) NaOEt, HOEt, heat
My confusion is in the first few steps. I thought KMnO4, etc. just added OH groups to either side of the double bond. Does the cyclohexene end up being broken? If so, how?
Yes, from the above sequence of reaction we can obtain that product. Does the... View the full answer