CH3-CH3-O-CH2-CH3 is a symmetrical ether? -- the two ethyl groups do not look identical on both sides.
Left alkyl group is CH3CH3- (both carbons are have 3 hydrogens attached).
Right alkyl group is -CH2CH3 (1st carbon with 2 hydrogens and second carbon with 3 hydrogens attached).
When it comes to the R groups being "identical" does it not matter how many protons are attached, or just how many carbons are in the chain?
Does the octet rule not apply here?
CH3-CH3-O-CH2-CH3 is a unsymmetrical ether. Yes it does matter... View the full answer