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What is the difference in the chemical reactions in Ca(OH)2 and the dibasic base of the solution? Please explain how hydrochloric acid to calcium hydroxide was used and its outcome. Additional information is in the links below.


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Previouse Information 2. Revise your explanation if needed. Write it here. in this case we have concentration of base half than that of concentration of acid so we need double the volume of base to neutralize acid completely , and that volume of base we can calculate from the titration formula . ---->As it is 1 : 1 acid base titration , means we need equal volume of acid and base to completely react and neutralized each other . So as we have half concentration of base than that of acid so we will use double the amount/volume of base to neutralize acid completely , and that volume (V1) of base we can calculate from titration formula BASE : ACID nv1 Mv1 Vv1= nv2 Mv2 Vv2 Vv1= (Mv2 Vv2)/Mv1 So all solutions will follow the above titration formula Score: This section is locked: response cannot be modified. 0/2

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it Part 6: Testing with a Dibasic Base {A} By now you should be very confident in your explanation to provide accurate predictions for many different titrations. Now, we're going to try a test using a different chemical reaction: adding hydrochloric acid to calcium hydroxide. Calcium Hydroxide, Ca.(0H)2 , is called a dfbaslc base. It has two hydroxide ions for every molecule, so it can acoept two hydrogen ions per molecule. 1. Start by writing out the balanced chemical equation for this reaction. BIQ E E %E|fx Score: 0 f 2

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2. In the next section, you'll see a titration where 0.050 M AC is added to a flask initially containing 40.0 ml of 0.0189M Ca(OH )2. Use the explanation you developed in the previous sections to predict the amount of AC/ that will need to be added to neutralize this solution. Hint: You may need to modify your explanation for what causes the solution to be neutralized to account for the fact that calcium hydroxide has two OH- ions in each molecule. BI U E E 0 fx Score: 0 / 5

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